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Find the equation of the circle whose center and radius are given. center ( 5, 6), radius = 3
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the general form is (x - a)^2 + (y - b)^2 = r^2 where (a,b) is the center and r = radius
is this right\[(x-5)^2+(y-6)^2=3\]
The equation of a circle is (x – h)^2 + (y – k)^2 = r^2 The radius is r The x value of the center is h and the y value is k
3 squared at the end
its not 3 its 3^2
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\[(x−5)2+(y−6)2=3^2\]
otherwise ok
That's correct
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