Keegan says that a quadrilateral is a square if and only if it is a rectangle. Is this a true biconditional statement?
chooses:
1) Yes, because all squares are rectangles.
2 )Yes, because all rectangles are squares.
3) No, because all squares are not rectangles.
4) No, because all rectangles are not squares.
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OpenStudy (faiqraees):
Are all rectangles squares?
OpenStudy (jsizzie101):
@FaiqRaees well I guess....? aren't rectangle special squares?
OpenStudy (faiqraees):
|dw:1458854047564:dw|
Is this a rectangle ?
OpenStudy (jsizzie101):
yes
OpenStudy (faiqraees):
is that a square?
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OpenStudy (jsizzie101):
well no I guess... sorry I suck at geometry
OpenStudy (faiqraees):
Yes pefect. So not all rectangles are squares, right?
OpenStudy (jsizzie101):
right ok. thanks
OpenStudy (faiqraees):
Okay so look at the main part of the question now
OpenStudy (faiqraees):
|dw:1458854299408:dw|
Is this a square? Is this a rectangle?
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OpenStudy (jsizzie101):
A square
OpenStudy (faiqraees):
And is a rectangle?
OpenStudy (jsizzie101):
no. so the answer to my original question would be D right?
OpenStudy (faiqraees):
No it is a rectangle
OpenStudy (faiqraees):
See all squares are rectangles but not all rectangles are squares
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OpenStudy (jsizzie101):
ohhhhhhhhhhhhh ok I get
OpenStudy (faiqraees):
Oh i am sorry it says biconditional which means both have to be true so the answer is no becuase not all rectangles are squares