Question

What is the solution set for this linear-quadratic system of equations?
y = x^2 − x − 12
y − x − 3 = 0

Answer 1

Rewrite the second equation in terms of x

Answer 2

Ah! Okay. Thank you. I haven't done this stuff in a long time.

Answer 3

Can you do it now?

Answer 4

Okay. So what i got was x=y-3 and now i'm lost.

Answer 5

In terms of x means
y = x +3

Answer 6

Oh crap. Sorry .

Answer 7

Now substitute it in first equation

Answer 8

OH! Okay. I get it now.