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Mathematics 9 Online
OpenStudy (taylor.joe):

What is the solution set for this linear-quadratic system of equations? y = x^2 − x − 12 y − x − 3 = 0

OpenStudy (faiqraees):

Rewrite the second equation in terms of x

OpenStudy (taylor.joe):

Ah! Okay. Thank you. I haven't done this stuff in a long time.

OpenStudy (faiqraees):

Can you do it now?

OpenStudy (taylor.joe):

Okay. So what i got was x=y-3 and now i'm lost.

OpenStudy (faiqraees):

In terms of x means y = x +3

OpenStudy (taylor.joe):

Oh crap. Sorry .

OpenStudy (faiqraees):

Now substitute it in first equation

OpenStudy (taylor.joe):

OH! Okay. I get it now.

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