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Mathematics 13 Online
OpenStudy (marcelie):

help please .. find the derivative

OpenStudy (marcelie):

hartnn (hartnn):

31st? what have u tried?

OpenStudy (marcelie):

yes. number 31

OpenStudy (marcelie):

come back @hartnn

hartnn (hartnn):

done with the derivative part ? just need help with algebraic part?

OpenStudy (marcelie):

derivative

hartnn (hartnn):

chain rule \((x^2+y^2)^2)' = 2 (x^2+y^2) (2x + 2y dy/dx) \)

OpenStudy (marcelie):

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