Question

I have a picture attached. I don't see how i got part C incorrect. I plugged in (-3) to the inverse of h.

Answer 1

for a shortcut,
\(f^{-1} o f (x) = x\)
always.

How did you get -8/3?

Answer 2

ohh, you just plugged -3 in \(h^{-1}x\) !

Answer 3

that will give you \(h^{-1}(-3)\)

Answer 4

i plugged -3 into the inverse of h. -3-13/6 and got -8/3

Answer 5

but that will give you
\(h^{-1}(-3)\)
right?