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OpenStudy (fantageplayer):
Consider the functions f(x) = 2x + 1 and g(x) = x2 − 10. What is the value of f[g(3)]?
39
−3
−7
−1
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OpenStudy (faiqraees):
First find the value of the function g(3)
OpenStudy (fantageplayer):
3x2−30?
OpenStudy (faiqraees):
No input 3 instead of x
OpenStudy (fantageplayer):
oh so divide then?
OpenStudy (faiqraees):
no
g(3)=(3)²-10
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OpenStudy (fantageplayer):
but dont you divide (3)^2-10/3 if you want g?
OpenStudy (fantageplayer):
sorry im bad at this
OpenStudy (faiqraees):
No no it is not 3g it is g(3) which is a different thing. g(3) just means the value when x is 3
OpenStudy (fantageplayer):
ohhhhhhhhhhhhhhhhh
OpenStudy (faiqraees):
for example if x = 1 then x²-10 = -9 so g(1) = -9
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OpenStudy (fantageplayer):
i see
OpenStudy (fantageplayer):
does x = 3 for x too?
OpenStudy (fantageplayer):
@radar @FaiqRaees
OpenStudy (fantageplayer):
does x = 3 for f too?*
OpenStudy (faiqraees):
no did you find the answer for g(3)
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OpenStudy (fantageplayer):
how do i do that?
OpenStudy (faiqraees):
for g(3) replace 3 in place of x
OpenStudy (fantageplayer):
so thenit would be -3?
OpenStudy (faiqraees):
no g(x) = x²-10
g(3) = 3²-10
g(3)=9-10
OpenStudy (radar):
FaiqRaees is doing an excellent job, focus, study the posts.
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OpenStudy (mrcoolguy):
sorry
OpenStudy (fantageplayer):
ohhhh i mean -1
OpenStudy (faiqraees):
yep since g(3) = -1 so you can replace that into f(g(3))
f(g(3)) = f(-1)
OpenStudy (faiqraees):
now find the value of f(-1)
OpenStudy (fantageplayer):
-1?
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