How do we construct a perpendicular from a point on a line in only 3 steps? http://www.euclidea.xyz/game/#/packs/Beta/level/ErectPerp
Unfortunately this is 4 steps: 1 to draw the radius on either side of the point, 2 to mark the points above, and 1 to actually draw in the perpendicular line.
m8 this sounds very hard
You also need 1 L only right?
For 1 L, there is one simple idea.. mark any two points on the line.. Then construct the angle bisector
|dw:1459049543425:dw|
But that would make 4 E... hmm...
Yeah this is my problem exactly haha.
3E seems impossible to me.
NO IT'S POSSIBLE :o WOAH!!!!! :P
I think I got it :P
Hahaha ok I am waiting to be amazed xD
Got it :D
1. We take some random point outside the line
|dw:1459050090426:dw|
Then we construct a circle from that point to the point we want to erect perpendicular at
|dw:1459050119978:dw|
Next |dw:1459050204342:dw|
Join our real-time social learning platform and learn together with your friends!