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A six-sided fair die is rolled 4 times in a row. The probability of getting a 4 only on the last trial is
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you got to work out the scenario its not 4, not 4 , not 4, 4
P(4) = 1/6 , P(not 4) = 5/6 multiply these probabilities
the throws are independent of each other so the probs are multiplied required probability = 5/6 * 5/6 * 5/6 * 1/6
i'm trying to help u here hailey at least work with me
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