Given tht ..
a^2 + 6b = -14
b^2 + 8c = -23
c^2 + 4a = 8

find ab + bc + ca

Question

Given tht .. 
a^2 + 6b = -14 
b^2 + 8c = -23 
c^2 + 4a = 8

find ab + bc + ca

luckyness · Answer

Please post your question!~ :)

rishavraj · Answer

@ganeshie8

rishavraj · Answer

@mathmath333  bhai try kr ek baar

rvc · Answer

mujhe assignment likhe de beta
chem ka assignment likh rahi hu
bahut kaam hai

rishavraj · Answer

kya gunda banegi ....lol...xD 
try kr ...mai bhi kr raha hun

rvc · Answer

masti nahi kar rahi

rishavraj · Answer

mai serious hun yaar......try kr.....honestly

rvc · Answer

kya hai ans?

rishavraj · Answer

nahi pata -_- .... lol NTSE ka hai .....

rvc · Answer

ans find kar
mujhe ek ans mila
but im sure its wrong xD

rishavraj · Answer

bata to sahi

rishavraj · Answer

majak kr rahi ...itni jldi ho gaya -_-

rvc · Answer

India ki team ko bhula :)
tag  kar

rishavraj · Answer

krte ja :) ... :P

rishavraj · Answer

apna answer to bata de

rvc · Answer

ab+bc+ca=3b+4c+2a+1

rvc · Answer

brb in half an hour
@ganeshie8

rishavraj · Answer

sach mein yaar bahut ganda majak tha -_- ..huh really ??? -_-

rishavraj · Answer

@rebeccaxhawaii

ganeshie8 · Answer

what do we know about a, b, c ?
are they integers ?

rvc · Answer

back :P

rishavraj · Answer

It is just mentioned ....
Given tht ..
a^2 + 6b = -14
b^2 + 8c = -23
c^2 + 4a = 8
find ab + bc + ca

@ganeshie8  previously there was an error ...
@rvc *clap clap ...... hurrrrrrrrrrrrrxD

rishavraj · Answer

and one more thing I dont know the answer ....... not having the answer key .... 
rvc  solve krna suru ..... majak mt kariyo -_-

rvc · Answer

xD
(a^2+b^2+c^2)

ganeshie8 · Answer

is this a multiple choice ?

rvc · Answer

(a+b+c)^2

rvc · Answer

haan woh bata pehele
mcq hai kya?

rishavraj · Answer

a)26    b)16    c)32    d)25

and yeah sorry for late reply ...... this internet is killing me.....
rvc tu ky aganeshie k baatein repeat kr rahi hai ..... :P lol jst messing

rishavraj · Answer

@ganeshie8  bhai kuch pata lage.... I got no clue..... bahut kuch try kr liya -_-

rishavraj · Answer

bhai lol hit and trial s ho gaya....lagta hai NTSE wale chahte nahi the k koi full score kare -_- @ganeshie8  @rvc

rishavraj · Answer

26 answer aaya ....... -_-

rvc · Answer

how?

rishavraj · Answer

@rvc kya kregi jaan k...sab moh maya hai  ...lol xD

rishavraj · Answer

@ganeshie8  u there???? :/

rvc · Answer

-.-

rishavraj · Answer

hit and trial -_-

rishavraj · Answer

@rvc  hmmmm ??

ganeshie8 · Answer

have you deleted the question ?

rishavraj · Answer

nope.... bt still here it is 

It is just mentioned ....
Given tht ..
a^2 + 6b = -14
b^2 + 8c = -23
c^2 + 4a = 8
find ab + bc + ca

rishavraj · Answer

@ganeshie8  bt trust they didnt want students to solve this question -_-

rishavraj · Answer

@hartnn  join the party :P

anonymous · Answer

a b + b c + c a = 26

rishavraj · Answer

yup I got tht bt by hit and trial method.... @robtobey  lemme know if theres any valid method

rishavraj · Answer

don't tell me everyone viewing this is question is AFK -_-

rishavraj · Answer

@robtobey  u gonna tell ???? :/

anonymous · Answer

Working on it.

rishavraj · Answer

okkk .... cool ..... xD

pawanyadav · Answer

a=-2 , b=-3 and c=-4

rishavraj · Answer

@Pawanyadav  which method did u use??

pawanyadav · Answer

I think there is some mistake...wait

rishavraj · Answer

trust me I hav been waiting from last 2 hrs -_-

rishavraj · Answer

btw I got the same values bt by Hit and Trial method @Pawanyadav

pawanyadav · Answer

After too many manipulation I got 
(a+2)^2+(b+3)^2+(c+4)^2=0
This is only possible when
a=-2,b=-3 and c=-4

radar · Answer

@Pawanyadav You're good.

rishavraj · Answer

if u can plz show the work......as I told before ...I aint having the answer key....bt got the same values

pawanyadav · Answer

Is answer 26?

rishavraj · Answer

no idea bt I got te same answer.... and tbh nice job... HATS OFF man @Pawanyadav

pawanyadav · Answer

Add all three equations..
So you will get..
a^2+4a +b2 +6b +c2+8c+29=0
From a2+4a ,we are getting ideas of (a+2)^2
Similarly with (b+3)^2 and (c+4)^2
And we can break 29=4 + 9 + 16


..and I got the answer ..that I already told.

rishavraj · Answer

no worries got it :))

anonymous · Answer

Refer to the attachment from Mathematica v9.
The second part is a lengthy human calculation where Mathematica 
does the intermediate computations.

rishavraj · Answer

@robtobey  this internet is literally killing me -_- *I am dead ......

anonymous · Answer

?  Where does it hurt ?

rishavraj · Answer

down there..... I mean at the bottom of the heart :P

rishavraj · Answer

bt really wht u used to solve it -_- 
damn freaky values

anonymous · Answer

Well I hope that you recover.
Have to bail out now.

rishavraj · Answer

lol yeah...... just keep on praying ... :P lol 
thanks though ..... wasnt knowing it was gonna take like 2 hrs on here :P

rishavraj · Answer

@mathmath333  u must hav a look on this ...... tbh

rishavraj · Answer

@Vijeya3   @563blackghost

rishavraj · Answer

so thanks to all for their participation :)))

vijeya3 · Answer

Kaunse year ke NTSE ka question tha ye?@rishavraj

rishavraj · Answer

pata nahi yaar subah check kr k bata dunga ....

vijeya3 · Answer

-_- okay

rishavraj · Answer

@Vijeya3  dont worry I wont let u miss me ...lol 
aise qurstions post krte rahunga :)

vijeya3 · Answer

-_-
Cool!Cuz I have to give NTSE this year..so u'll be helping me

rishavraj · Answer

ooo for sure girlll.....any time ....... jst lemme know....

vijeya3 · Answer

:)

rishavraj · Answer

:) ;P >_< >.< -_- <3 > << ho gaya???

vijeya3 · Answer

-_-
yeah

rishavraj · Answer

cool....xD

mathmath333 · Answer

$\large \color{black}{\begin{align}
& (a+b+c)^{2}=a^{2}+b^{2}+c^{2}+2(ab+bc+ca)\hspace{.33em}\~\
& -29=a^{2}+b^{2}+c^{2}+2(3b+4c+2a)\hspace{.33em}\~\
& (ab+bc+ca)\implies (3b+4c+2a)\hspace{.33em}\~\
\end{align}}$

just some similarity

rishavraj · Answer

hmmmm I see