Question

help

Answer 1

@ganeshie8

Answer 2

@freckles

Answer 3

are you having trouble pluggin in values of x into 1.7x-0.4 ?

Answer 4

or are you having trouble finding the difference of actual value and predicted value?

Answer 5

I don't understand how I plug in the formula into the points the get the residual. Someone said that I can use my calculator because I have the Ti 84 sliver edition, If I do you that way how do I enter it into my calculator

Answer 6

residual is just actual output-predicted output

Answer 7

It so frozen treats for the first one so would I say 16

Answer 8

example:
row 1 values would be
x=10
y=16
ybar=1.7(10)-0.4=17-0.4=16.6
e=y-ybar=16-16.6=-.6

Answer 9

Okay so all I have to do is that for each one ?

Answer 10

yep
calculate ybar
then e which is just the difference in actual and predicted

Answer 11

Thanks so much I can do It on my own now

Answer 12

k

Answer 13

have fun

Answer 14

Thanks

Answer 15

@freckles

Answer 16

yes?

Answer 17

as you can see I finished solving the graph but How do I graph if that make since

Answer 18

you graph the ordered pairs (x,e)

Answer 19

plot the points (x,e)

Answer 20

for example do you know how to plot (10,-.6)

Answer 21

so 10, -6 for 1

Answer 22

you mean (10,-.6)

Answer 23

yes that's what I mean

Answer 24

yes

Answer 25

okay thanks and last question wheneven I finish graph how do I determine if its a good fit or not?

Answer 26

how to determine if a line is a good fit?
I would say if most of the points fall near or on a linear path

Answer 27

okay thank you

Answer 28

@freckles I'm here again I just don't think I did it right If its right I would say the line is not a good fit because it has no correlation

Answer 29

@freckles