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OpenStudy (anonymous):
Find all solutions in the interval [0,2pi]. (You do not need a calculator). 2sin^2x=1
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Directrix (directrix):
First step: Solve this for sin x 2( sin^2x) =1
OpenStudy (anonymous):
nevermind, i solved this problem now im working on another problem on the assignmen can you help me?
OpenStudy (anonymous):
wait ugh i still need to find the solutions
OpenStudy (anonymous):
I got sinx=+-1/2
OpenStudy (anonymous):
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