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Last one for the section find the integral of x/1+x^4
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try \[u=x^2\]
How did you get that?
same way i got to carnagie hall
Wait is it because when you differentiate you can get xdx all alone on one side?
practice
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\[u=x^2\\ du=2xdx\] a good start
So 1/2du=xdx
yes, which is just what you have, and your integral will look real real (real) familiar, since we just did one exactly like it
1/1+u^2du with 1/2 in front of integral
yup
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:) that wasn't bad just a little tricky at the beginning
no not too bad, just like the last one
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