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Help please !!! How do i do d.
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@Directrix
@hartnn
@freckles
v(t) = 3(t-3)(t-1) right?
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yes
find the critical points by solving 3(t - 3)(t - 1) = 0
then you can find the values of t when v(t) > 0
what are the 2 values of t when v(t) = 0?
|dw:1459280689151:dw|
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t = 3 and t = 1 for v(t) = 0
Now one way to do this is to find values of v(t) when t < 1 , 2<t < 3, and t > 3
sorry thats 1 < t < 3
brb..
- find if v(t) is > 0 or less than 0. eg when t = -2 v(t) = 3(-2-3)(-2-1) which is positive so t<1 for positive direction
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now check the other 2 intervals and you'll get the answer gotta go right now.
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