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Algebra 13 Online
OpenStudy (graceland00):

Will medal if right!

OpenStudy (graceland00):

Factor completely 4x3 + 28x2 + 7x + 49.

OpenStudy (graceland00):

(x − 7)(4x2 + 7) (x − 7)(4x2 − 7) (x + 7)(4x2 + 7) (x + 7)(4x2 − 7)

OpenStudy (anonymous):

Can you factor the first two terms and last two terms separately?

OpenStudy (graceland00):

Like multiply them?

OpenStudy (anonymous):

4x^2 (x + 7)

OpenStudy (anonymous):

Tell me what you get when you do htis

OpenStudy (anonymous):

yes it would be 4x^2 (x + 7)

OpenStudy (anonymous):

(x + 7)(4x^2 + 7)

OpenStudy (anonymous):

that would be you answer!!

OpenStudy (graceland00):

sorry i was trying to work it out but didn't really know how

OpenStudy (graceland00):

thank you though

OpenStudy (anonymous):

It would be c

OpenStudy (anonymous):

Simplifying 12(x2 + 3x + -18) = 0 Reorder the terms: 12(-18 + 3x + x2) = 0 (-18 * 12 + 3x * 12 + x2 * 12) = 0 (-216 + 36x + 12x2) = 0 Solving -216 + 36x + 12x2 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), '12'. 12(-18 + 3x + x2) = 0 Factor a trinomial. 12((-6 + -1x)(3 + -1x)) = 0 Ignore the factor 12. Subproblem 1Set the factor '(-6 + -1x)' equal to zero

OpenStudy (anonymous):

thats how i got mine

OpenStudy (anonymous):

4x3+28x2+7x+49

OpenStudy (graceland00):

thanks :P

OpenStudy (anonymous):

Final result : (4x2 + 7) • (x + 7)

OpenStudy (anonymous):

No Problem!!! Have a great day! You may close the question

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