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Algebra
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OpenStudy (graceland00):
Will medal if right!
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OpenStudy (graceland00):
Factor completely 4x3 + 28x2 + 7x + 49.
OpenStudy (graceland00):
(x − 7)(4x2 + 7)
(x − 7)(4x2 − 7)
(x + 7)(4x2 + 7)
(x + 7)(4x2 − 7)
OpenStudy (anonymous):
Can you factor the first two terms and last two terms separately?
OpenStudy (graceland00):
Like multiply them?
OpenStudy (anonymous):
4x^2 (x + 7)
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OpenStudy (anonymous):
Tell me what you get when you do htis
OpenStudy (anonymous):
yes it would be 4x^2 (x + 7)
OpenStudy (anonymous):
(x + 7)(4x^2 + 7)
OpenStudy (anonymous):
that would be you answer!!
OpenStudy (graceland00):
sorry i was trying to work it out but didn't really know how
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OpenStudy (graceland00):
thank you though
OpenStudy (anonymous):
It would be c
OpenStudy (anonymous):
Simplifying
12(x2 + 3x + -18) = 0
Reorder the terms:
12(-18 + 3x + x2) = 0
(-18 * 12 + 3x * 12 + x2 * 12) = 0
(-216 + 36x + 12x2) = 0
Solving
-216 + 36x + 12x2 = 0
Solving for variable 'x'.
Factor out the Greatest Common Factor (GCF), '12'.
12(-18 + 3x + x2) = 0
Factor a trinomial.
12((-6 + -1x)(3 + -1x)) = 0
Ignore the factor 12.
Subproblem 1Set the factor '(-6 + -1x)' equal to zero
OpenStudy (anonymous):
thats how i got mine
OpenStudy (anonymous):
4x3+28x2+7x+49
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OpenStudy (graceland00):
thanks :P
OpenStudy (anonymous):
Final result :
(4x2 + 7) • (x + 7)
OpenStudy (anonymous):
No Problem!!! Have a great day! You may close the question
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