c=ax-bx
Joseph claims that if a, b, and c are non-negative integers, then the equatoin has exactly one solution for x.
Select all cases that show Joseph's claim is incorrect.

Question

c=ax-bx
Joseph claims that if a, b, and c are non-negative integers, then the equatoin has exactly one solution for x. 
Select all cases that show Joseph's claim is incorrect.

dayakar · Answer

c= ax-bx
c= x(a-b)  [ taking x as common]

x(a-b) =c

x= c/ (a-b)   this is the solution and $$a-b \neq 0$$