Question

c=ax-bx
Joseph claims that if a, b, and c are non-negative integers, then the equatoin has exactly one solution for x.
Select all cases that show Joseph's claim is incorrect.

Answer 1

c= ax-bx
c= x(a-b) [ taking x as common]

x(a-b) =c

x= c/ (a-b) this is the solution and \[a-b \neq 0\]