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If F(x) =2x/x-3 And FoG(x) =5x What is g(x)?
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Fx x gx=5x Gx=5x/fx
HI!!
that answer is kinda silly right?
\[f(g(x)) = \frac{2g(x)}{g(x) - 3} = 5x\] solve for g(x)
\[2g(x) = 5x(g(x) - 3)\] \[5x g(x) - 2 g(x) = 15x\] \[g(x) (5x-2) = 15x\] \[g(x) = \frac{15x}{5x-2}\]
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that should work i was going to suggest that \[F^{-1}\circ F(x)\circ G(x)=F^{-1}(5x)=G(x)\]
\[F(x)=\frac{2x}{x-3}\\ F^{-1}(x)=\frac{3x}{x-2}\] \[F^{-1}(5x)=\frac{3\times 5x}{5x-2}\]
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