Question

Let x=4 and y=-2. Evaluate(x^2-y^2(10-y^2)/ 3)^2.

Answer 1

Whenever there's an x, replace it with 4, whenever there's a y, replace it with -2. Then evaluate.

Answer 2

\(\left({\color{brown}{ x}}^2-{\color{blue}{ y}}^2\cfrac{10-{\color{blue}{ y}}^2}{3} \right)^2\qquad
\begin{cases}
{\color{brown}{ x}}=4\\
{\color{blue}{ y}}=-2
\end{cases}\implies \left({\color{brown}{ 4}}^2-{\color{blue}{ (-2)}}^2\cfrac{10-{\color{blue}{ (-2)}}^2}{3} \right)^2\)

Answer 3

mhm ^^