Question

What is the area of a hexagon with the radius of 5 inches?

Answer 1

how many sides does a hexagon have anyway?

Answer 2

6 I think?

Answer 3

yeap, it has 6, HEXA = 6, thus \(\textit{area of a regular polygon}=\cfrac{1}{4}ns^2\ cot\left( \frac{180}{n} \right)\qquad
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of one side}
\end{cases}\)

Answer 4

Would it be 64.95?

Answer 5

what did you get for the cotangent anyway?

Answer 6

The what?

Answer 7

http://www.mathopenref.com/polygonregulararea.html

Answer 8

\(\textit{area of a regular polygon}=\cfrac{1}{4}ns^2\ cot\left( \frac{180}{n} \right)\qquad
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of one side}
\end{cases}\)

plug in those values, see what you get