Question

I have five table to do but need help getting started please.
x 1 2 3
y 2 4 8
Which table will have the greatest value of y when x = 7?

Answer 1

`which` I can see the only table ? where are the others?

Answer 2

I wasn't wanting the answer I just didn't know how to get started if x=7...what do I do?
Do I multiple 2 * 7 for x?
the other tables are
x 1 2 3
y 14 26 38

x 1 2 3
y 3 12 27

x 1 2 3
y 12 22 32

Answer 3

for the first table, for every x, y common difference of 12
the second table : for every x y is increase an ADDITIONAL of 6 with initial 9.
so 3+9=12 (when x =2)
12+15=27 (when x=3)
27+21=48 (when x=4) and so on.

The 4th table has a common difference of 10.

Clearly the 2nd table will be much higher when x =7

Answer 4

one thing to always try is see if the difference between y values is the same
in your first table
x 1 2 3
y 2 4 8

4-2 is 2 and 8-4 is 4 so it's not "linear" It is going up faster than linear

however, your second table shows
x 1 2 3
y 14 26 38
26-14 is 12 and 38-26 is also 12
that means it's a line with slope 12 (change in y is 12 divided by change in x is 1)
y-14 = 12(x-1) in point slope form, or
y= 12x +2 in slope-intercept form

Answer 5

Your fourth table
x 1 2 3
y 12 22 32

has 22-12= 10 and 32-22 = 10
so another line, with slope 10
y-12= 10(x-1) or
y= 10x +2

Answer 6

The first table look for a constant multiple. For example
x 1 2 3
y 2 4 8

4 is 2*2
and 8 is 2*4

that means it's geometric,
y= 2^x

when x is 7 you get y = 2^7 = 128

Answer 7

the 3rd table
x 1 2 3
y 3 12 27

is a bit tricker. notice we can "factor out a 3" for the y values:
3*1 3*4 3*9
and ignoring the 3's we have 1 4 9
no constant difference and no constant multiple. so we look for squares or cubes (if we are lucky). in this case those are squares: 1^2 2^2 3^2

so the table is
x 1 2 3
y 3*1^2 3*2^2 3*3^2

or in general y= 3 x^2
when x =7, you get y = 3*49= 147

Answer 8

I was not about to give you direct answer.
just wanted to see what type of help needed here.