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definite integral.
I got 0.5
that is right
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thank you!!
\(\color{#000000}{ \displaystyle e^{-2 \ln x} =x^{-2} }\) \(\color{#000000}{ \displaystyle \int_1^2x^{-2}dx=\left.-\frac{1}{x}\right|_1^2=-\frac{1}{2} --\frac{1}{1}=-\frac{1}{2}+\frac{1}{1}=\frac{1}{2} }\)
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