Question

Will Give Medal!

Solve: 16x^2 − 81 = 0.

x = 4, 9
x = −4, −9
x = 9 over 4, x = −9 over 4
x = 81 over 16, x = −81 over 16

Answer 1

Do uknow
a^2-b^2=?

Answer 2

a^2-b^2=(a+b)(a-b)

Answer 3

what do you mean...?

Answer 4

U hv to usethis formula in math

Answer 5

oh ok i THINK i know what you are talking about...

Answer 6

\(\color{#000000}{ \displaystyle 16x^2-81 =0 }\)
\(\color{#000000}{ \displaystyle 16x^2=81 }\)
\(\color{#000000}{ \displaystyle (4x)^2=9^2 }\)
\(\color{#000000}{ \displaystyle 4x=\pm 9 }\)

Answer 7

Now tell me
(4x)^2=?

Answer 8

Ok i got the 3rd one is that correct?

Answer 9

and16x

Answer 10

Yes correct!!!!

Answer 11

yay (:

Answer 12

Thanka

Answer 13

U r most welcome!!!!