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Mathematics 6 Online
OpenStudy (benlindquist):

http://prntscr.com/ao096r

OpenStudy (benlindquist):

@CheesecakeKitten @sleepyjess @JustDoubleChecking @AloneS

OpenStudy (justdoublechecking):

I have no idea on this one... Sorry.

OpenStudy (benlindquist):

(Rectangle) A=lw A=(8cm)(5cm) A= 40cm (SemiCircle) A = 12 π r 2 1 A = 2 π(4 cm) A= 25.13 Add the areas of the simpler figures together to find the total area of the composite figure. Area of rectangle + Area of semicircle 22 40cm +25.13cm The area of the composite shape is around 65.13 cm i got something wrong in this

OpenStudy (anonymous):

first find the area of the semicircle above then fin the asrea of the rectangle below

OpenStudy (anonymous):

*area

OpenStudy (benlindquist):

3x3.14

OpenStudy (anonymous):

Area of a semicircle is\[\frac{ \pi r ^{2} }{ 2 }\]

OpenStudy (benlindquist):

and the rectangle WxH and then go from there

OpenStudy (anonymous):

the rectangle is length x breadth

OpenStudy (anonymous):

then add the areas of the two

OpenStudy (benlindquist):

Semi Circle = πr22 Rectangle = Length x Breadth 9 x 5 = 45 45 + 69.08 = 114.08

OpenStudy (benlindquist):

@Joshtray

OpenStudy (anonymous):

ive not seen the dimensions

OpenStudy (anonymous):

what is the radius, what are the dimensions

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