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Solving logarithm equations
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\[\log_{2} (9x+5)- \log_{2} (x^2-1) =2\]
So let's look at some logarithmic rules first. \[\log_a (x) - \log_a (y) = \log_a \frac{ x }{ y }\] And \[\log_a x = y \rightarrow x = a^y\] How can you apply these rules to this question?
on my equation i will divide (9x+5) and (x^2-1)
Write out the full equation now, so I can make sure you have everything. :O
\[\log_{2} (9x+5)/ (x^2-1) =2\]
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Yes, so now apply the second rule I gave you. :D
2^2= (9x+5)
What happened to (x^2 - 1)?
Its divide by (9x+5)
Yeah so \[\frac{ 9x + 5 }{ x^2 -1} = 2^2\]
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