Question

I can't seem to solve this using logs:
Solve: x^(x-1) = (2^256)-1

Answer 1

You can't use logs to solve this question

Answer 2

At least not directly

Answer 3

I don't think this will help, but it's interesting that:
\[x^{x-1}=(2^{128}+1)(2^{128}-1)=(2^{128}+1)(2^{64}+1)(2^{64}-1)\]
\[=...=\prod_{n=0}^{7}( 2^{ 2^n} + 1) \]
:P