How does increasing the pop. standard deviation affect z? How does increasing the number of scores in a sample affect z? How does increasing the difference between the sample mean and the original population mean affect z? Does z Increase or Decrease?
Why not look up (if necessary) and type in the formula for "z-score?" What parameters (variables) affect the z-score?
I meant for the last one
i think it'd be helpful if you were to type out the formula for the z score. Mind doing that?
z=m-u/om
z=m-u/om \[z=\frac{ x-\mu }{ \sigma}\]
How does increasing the pop. standard deviation affect z? Where is that sigma located?
it decreases z
right. if the pop std dev incr, z decr. yes.
and, as the number of scores increase, z decreases?
"How does increasing the number of scores in a sample affect z?" What's your basis for saying that z decreases? Need to share the formula for sample std. dev.; it's different from that for population std. dev.
since it is in the denominator, it will decrease our answer
Decrease our what?
z
Yes, the SAMPLE z would decrease if n were to increase.
and as standard error increases, z increases
or m-u
Yes. Mind asking questions, if you have any more?
is the difference between the sample mean and the population mean m-u or is it the standard error?
Look up "standard error of the mean" on the 'Net, please. As a general rule, the sample mean and the pop'n mean are the same quantity, but the std. deviations differ.
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