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Engineering 7 Online
OpenStudy (anonymous):

Can you simplify the following equation for a circuit? (A⊕B)+(A NOR B) =Q?

OpenStudy (kenljw):

(A⊕B)+(A NOR B) =Q? A NOR B = A'B' A+B+A'B' = 1 assumes A⊕B = A+B Proof (A+B+A'B)' = A'B'(A+B) = 0

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