Question

Help w/ 2 questions please?

will Medal + Fan !

Answer 1

\[\large\rm Domain = \frac{x^2-16}{x+4} \]\[\large\rm Domain = \frac{(x+4)(x-4)}{x+4} \]\[\large\rm Domain = \frac{ \cancel{(x+4)}(x-4)}{\cancel{(x+4)}} \]\[\large\rm Domain =x-4 ~~~~~~x\neq-4 \]

Answer 2

or you could do it that way! lol

Answer 3

Ok I see what you did. Thanks for adding the steps as well! & For the second one I think it'd be C.

Answer 4

i thought the second one was B. but idk

Answer 5

Correct

Answer 6

C is correct

Answer 7

Thank you, I appreciate it..

Answer 8

No problem