Question

Can someone please help me with this math question? Please? I will fan and give a medal!

Question-
Simplify the following exponential expressions.
(-.07xy^4)(.3x^3y)

Answer 1

multiply -.07 and .3
multiply x amd x^3
multply y^4 and y

Answer 2

use law of exponents for the last two

Answer 3

then you will find your answer

Answer 4

Like this @freckles ?
(-.07xy^4)(.3x^3y)
=
-.07*.3 = -0.021
x*x^3= 2x^3
y^4*y= 2y^y4

Answer 5

first product is correct
the last two products you found is incorrect
where is the 2 coming from in front

if you have 1 factor of x and then you put another 3 factors of x with it how many factors of x do you have?

Answer 6

@jhonyy9 could you help me finish this? frecles is offline at the moment... Please?

Answer 7

x*x^3 = ?
so than you know that a*a^2 = a^(1+2) =a^3

Answer 8

abby are you here ?

Answer 9

So x*x^3= x^4?

Answer 10

yes exactly you are right

Answer 11

and y^4 *y = ?

Answer 12

y*5?

Answer 13

yes so now you have got the right answer sure - yes ?

Answer 14

ok. ?

Answer 15

bye bye

Answer 16

I'm sorry my laptop messed up... is the answer -0.021x^4y^5?

Answer 17

yes exactly

Answer 18

thank you for the help!! :)

Answer 19

was my pleasure

good luck

bye bye