okay so y= the numbers on the right the y colum and the equaions mean like so choice a is =y=4x, so take the first number on the x side and plug it in the equation= y=4*6
OpenStudy (anonymous):
so 4*6=24
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OpenStudy (flower2468):
wait no, 4*4=
OpenStudy (flower2468):
not 6, I i meant 4 oops
OpenStudy (anonymous):
so it would be 16
OpenStudy (flower2468):
and is that the number on the other side on 4 in the table?
OpenStudy (anonymous):
6
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OpenStudy (flower2468):
no the number 16 is not which means that a is wrong
OpenStudy (anonymous):
okay
OpenStudy (flower2468):
now lets try B now plug in 4 in the eqation: y=5*4
OpenStudy (anonymous):
So it must be b
OpenStudy (flower2468):
well is 20, which is 5*4 on the other side in the y colum?
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OpenStudy (anonymous):
idk
OpenStudy (flower2468):
it is not, so I already tell you it is not c, because 4+7 does not=6
OpenStudy (flower2468):
so for D, 4+2=6 so that is right and 5+2=7 and 7+2=9 and 10+2=12 and 11+2=13
OpenStudy (flower2468):
so d is right because the rule is add2
OpenStudy (flower2468):
see how i did that?
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