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2b + c=6 b +c=6
change the sign of the second one.
3b + 2c = 12
water we exactly solving for thow?
Basically I am find the general term of a quadratic Formula: Tn=an^2 + bn + c 2a=4 a=2 T1=8 2(1)^2 + b(1) + c=8 2+b+c=8 -------------- b+c=6 T2=14 2(2)^2+b(2)+c=14 8+2b+c=14 -------------- 2b+tc=6
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