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Find the value of 53³ using the identity (x+y)³=x³+3x²y+3x²y+y³ Hint:53³=(50+3)³; therefore, x=50 and y=3.
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Well it says 53³ = (50+3)³ And we are using the identity (x+y)³=x³+3x²y+3x²y+y³. So (50+3)³ = (x+y)³, and x = 50, y = 3. Do you understand how x = 50 and y = 3?
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