Question

Light of wavelength 550 nm falls on a slit that is 3.70 ✕ 10-3 mm wide. How far from the central maximum will the first diffraction maximum fringe be if the screen is 12.0 m away?

Answer 1

Do you know the formula for that?
asintheta=(2n-1)lambda/2
a is the slit width..n can go from 1,2,...so on..

Answer 2

I tried to use the formula \[y_n = (n+1/2)*L*\lambda/a\] where n = 1, L = 12, lambda = 550x10^-9, and a = 3.70x10^-6 but it didn't work

Answer 3

Is the ans 0.891 m

Answer 4

No???? where did that come from

Answer 5

OHH college stuff... funnnnnn