Can you verify that these are correct? #4http://prntscr.com/aphfbh #5http://prntscr.com/aphj48 #6http://prntscr.com/aphjt9
for #4 the solution would be any point in the shaded region
#5 is wrong
so c would be a better choice for #4?
Yeah
ok and could you help with #5 cause i never really got how to graph that
Well , your answer is close for #5, you're just a little off You can use http://desmos.com/calculator to graph
while calculators can do the graphing for you, they are not very helpful on learning it
oh man, i was close, then it would be I, II, III
for \(\bf y\ge x-2\) you graph the line of y = x-2 then you shade the "true" area,
and that would be above the line
yes
how about #6?
well, using substitution \(\begin{array}{llll} {\color{brown}{ x}}=y-3\\ {\color{brown}{ x}}+3y=13\implies {\color{brown}{ y-3}}+3y=13 \end{array}\) what woiuld that give you for "y"?
\[y = 4\]
so then its A
yeap, y = 4 meaning x = y - 3 => 4-3 => 1
# 4 is c...because u have a dashed line...points ON the line r not solutions
\[x = y - 3 \] \[x + 3y =13\] x = 1 y =4 1 = 4 - 3 1 + 3(4) = 13
wait so what was number #5 because there's no 1,2,3
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