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Mathematics 6 Online
OpenStudy (domebotnos):

Can you verify that these are correct? #4http://prntscr.com/aphfbh #5http://prntscr.com/aphj48 #6http://prntscr.com/aphjt9

OpenStudy (stormer15):

for #4 the solution would be any point in the shaded region

OpenStudy (stormer15):

#5 is wrong

OpenStudy (domebotnos):

so c would be a better choice for #4?

OpenStudy (stormer15):

Yeah

OpenStudy (domebotnos):

ok and could you help with #5 cause i never really got how to graph that

OpenStudy (stormer15):

Well , your answer is close for #5, you're just a little off You can use http://desmos.com/calculator to graph

OpenStudy (jdoe0001):

while calculators can do the graphing for you, they are not very helpful on learning it

OpenStudy (domebotnos):

oh man, i was close, then it would be I, II, III

OpenStudy (jdoe0001):

for \(\bf y\ge x-2\) you graph the line of y = x-2 then you shade the "true" area,

OpenStudy (domebotnos):

and that would be above the line

OpenStudy (jdoe0001):

yes

OpenStudy (domebotnos):

how about #6?

OpenStudy (jdoe0001):

well, using substitution \(\begin{array}{llll} {\color{brown}{ x}}=y-3\\ {\color{brown}{ x}}+3y=13\implies {\color{brown}{ y-3}}+3y=13 \end{array}\) what woiuld that give you for "y"?

OpenStudy (domebotnos):

\[y = 4\]

OpenStudy (domebotnos):

so then its A

OpenStudy (jdoe0001):

yeap, y = 4 meaning x = y - 3 => 4-3 => 1

OpenStudy (texaschic101):

# 4 is c...because u have a dashed line...points ON the line r not solutions

OpenStudy (domebotnos):

\[x = y - 3 \] \[x + 3y =13\] x = 1 y =4 1 = 4 - 3 1 + 3(4) = 13

OpenStudy (domebotnos):

wait so what was number #5 because there's no 1,2,3

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