Question

Find the magnitude and direction of the vector. Round the length to the nearest tenth and the degree to the nearest unit.

Answer 1

Are we finding the hypotenuse, I assume?

Answer 2

the magnitude and direction of the vector

Answer 3

magnitude is how "long" it is, thus as aforementioned, it will be the hypotenuse

Answer 4

to find its "direction", is to find the angle it makes, thus, you're given the x,y values of the vector, so, use the inverse tangent function to get the angle :)

Answer 5

\(\begin{array}{llll}
<6&,&4>\\
\ x&,&y

\end{array}\qquad

\begin{array}{llll}
||<6,4>|| magnitude\implies \sqrt{x^2+y^2}\\
direction\implies angle\implies tan^{-1}\left( \frac{y}{x} \right)
\end{array}\)

Answer 6

magnitude is 7.2
@jdoe0001