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y is inversely proportional to the square of x and y=p for a particular value of x. Express the value of y in terms of p when this value of x is halved
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y invers proportional to square of x you can write y = 1/x^2
than y=p and express the y value when the value of x is halved - so this mean y = 1/((x/2)^2) y = 1/((x^2)/4) y = 4/(x^2)
sandy - how you think that will be this in term of p presented ?
so we know that y = 1/(x^2) y=p so result p = 1/(x^2) so than y= 4/(x^2) in term of p will be y = 4p right ?
Looks good.
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thank you for your opinion good luck bye bye
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