solve the system.
4(3x + y) + 2z = -7
3(x - 4y + 2z) = -16
3(5 + 3x) = -4(z - 4y)

Question

solve the system.
4(3x + y) + 2z = -7
3(x - 4y + 2z) = -16
3(5 + 3x) = -4(z - 4y)

rebeccaxhawaii · Answer

get all in standard form first
so
x+y+z=?

anonymous · Answer

im not sure

anonymous · Answer

Distribute the numbers into the parentheses first.
So for
4(3x + y)     you would distribute the 4 into 3x and then into y, making it
12x + 4y

Then do that for all the parentheses

anonymous · Answer

And for
3(x - 4y + 2z) you distribute the 3 into each coefficient, making it
3x - 12y + 6z

Can you try that for the last one?

anonymous · Answer

I have to go so try to do that and hopefully someone else will help you with the rest

anonymous · Answer

Did you understand the distribution?