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solve the system. 4(3x + y) + 2z = -7 3(x - 4y + 2z) = -16 3(5 + 3x) = -4(z - 4y)
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get all in standard form first so x+y+z=?
im not sure
Distribute the numbers into the parentheses first. So for 4(3x + y) you would distribute the 4 into 3x and then into y, making it 12x + 4y Then do that for all the parentheses
And for 3(x - 4y + 2z) you distribute the 3 into each coefficient, making it 3x - 12y + 6z Can you try that for the last one?
I have to go so try to do that and hopefully someone else will help you with the rest
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