Question

A square painting has an area of 1040 in2.

To the nearest tenth, what is the length of 1 side of the painting?

Answer 1

@texaschic101

Answer 2

The area of a square with side x is

\(A = x^2\)

You have the area, so you have

\(x^2 = 1040 ~in^2\)

All you need to do is take the square root of 1040 to find x, the side.
Use a calculator to find the square root of 1040.
Then round off to the nearest tenth.

Answer 3

The area of square = (sidelength)^2
1040 = L^2
L = rootof(1040)
L= 32.2

Here you go hope this helps :)

Answer 4

@logan13