In the shot put, an athlete throws a heavy metal ball through the air. The arc of the ball can be modeled by the equation y=-0.04x^2+.84x+2, where x is the horizontal distance, in meters, from the athlete and y is the height, in meters, of the ball. How far horizontally from the athlete will the ball land? (use the Quadratic Formula!)

Question

In the shot put, an athlete throws a heavy metal ball through the air.  The arc of the ball can be modeled by the equation y=-0.04x^2+.84x+2, where x is the horizontal distance, in meters, from the athlete and y is the height, in meters, of the ball.  How far horizontally from the athlete will the ball land?  (use the Quadratic Formula!)

welshfella · Answer

in quadratic formula for this equation 
a = -0.04,b = 0.84 and c = 2

welshfella · Answer

the equation to be solved is 
-0.04x^2 + 0.84x + 2 = 0

beacause y = 0  when the shot hits the ground