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find the value of theta for 0
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no can you solve for x in \[ x^3 = -\frac{1}{8} \]?
2^-3
you need to review cube roots x= -½ (because -½ * -½ * -½ = -⅛ that means in your problem sin theta= -½ now find the "inverse sin" but you (should) know sin 30 deg = ½
in case you did not know \[ \sin^3 \theta \text{ means } ( \sin \theta)^3 \]
I always associate "sin" with "y" in the unit circle -½ means the y value is negative. there are two quadrants with a negative y |dw:1460588921617:dw|
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