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Trigonometry
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how many solutions does sin^-1 (0) have on the interval [0,pi)
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So. Inverse sin of zero is asking, at what points on the unit circle is 0 the Y value of a point? The only place that this would be true is at 0 degrees. 0 degrees has a coordinate of (1, 0), notice how the Y value of 0. If you're thinking "What about pi??", the equation has a parenthesis on the outside of pi, like this: [0, pi). That means that it can be equal to 0, but must be less than pi. So the only solution is 0 degrees, or 0pi.
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