Using spherical coordinates, find the volume of the solid
inside $$z = (x^2 + y^2)^(1/2) $$
and bounded by $$ z^2 + x^2 + y^2 = 1, and z^2 + x^2 + y^2 = 4 $$

Question

Using spherical coordinates, find the volume of the solid
 inside $$z = (x^2 + y^2)^(1/2) $$
 and bounded by  $$  z^2 + x^2 + y^2 = 1, and z^2 + x^2 + y^2 = 4 $$

phi · Answer

can you sketch the region (volume) ?

anonymous · Answer

|dw:1460676107803:dw|   where  $$ 0<= p <= 2 $$ and  $$ 0 <= 	heta <= 2 \pi $$ 
but I can't find phi. :/

phi · Answer

in cylindrical coords,  x^2 + y^2  is r^2  (measured from the z-axis)
the cone has the equation z= r
|dw:1460676679805:dw|