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find the value of the expression: (sum difference formulas) cos(sin^-1(1/3)-tan^-1(1/2)
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subtraction angle formula for cosine here
\[\cos(a-b)=\cos(a)\cos(b)-\sin(a)\sin(b)\] put \[a=\sin^{-1}(\frac{1}{3}),b=\tan^{-1}(\frac{1}{2})\]
oops i made a typo sorry
\[\cos(a-b)=\cos(a)\cos(b)\color{red}+\sin(a)\sin(b)\]
get \[=\cos(\sin^{-1}(\frac{1}{2}))\cos(\tan^{-1}(\frac{1}{2}))\color{red}+\sin(\sin^{-1}(\frac{1}{2}))\sin(\tan^{-1}(\frac{1}{2}))\]
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of course you still have a pile of work to do
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