Question

Solve the following system using the elongation method.
2a+2b=4
4a-3b=8

Answer 1

You mean elimination?

Answer 2

Yes sorry!!

Answer 3

you would multiple the top equation \[(2a+2b=4)\] by negative 2 to get \[ -4a-4b=-8\]
then you combine them \[-4a-4b=-8\]\[4a-3b=8\] the -4a and 4a eliminate. however the -8 and 8 eliminate as well so this equation would be \[-7b=0\]so \[b=0\] :)

Answer 4

Thank you so much!!

Answer 5

then, you place it into the origional equation.
2a+2(0)=4
2a=4
a=2
:)