Question

The path of an electron, traveling at 3.7 × 104 meters/second, is making a right angle to a magnetic field. A single electron experiences a force of 2.2 × 10-15 newtons while in the field. What is the strength of the magnetic field? The value of q = -1.6 × 10-19 coulombs.

Answer 1

@Luigi0210

Answer 2

\(\sf F=q\times vB\) but at 90 degrees, it reduces to \(\sf F=q vB\), so the strength of the magnetic field is given by: \(\sf B=\dfrac{qv}{F}\)

Answer 3

read this http://www.feynmanlectures.caltech.edu/II_29.html