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3x^2+44x= -96
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ya that looks about right
I have to solve it I just don't know what do
hmm lets see if this helps 1st get everything on 1 side.. meaning add 96 to both so we should have 3x^2 + 44x + 96 = 0 now use the quadractic formula to solve for x \[(-b \pm \sqrt{b ^{2}-4ac})/2a\]
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