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Mathematics 16 Online
OpenStudy (elonasushchik):

hey! all the help needed huns!

OpenStudy (elonasushchik):

Solve open parentheses square root of 7 close parentheses to the 6 x power = 49x−6

OpenStudy (agent0smith):

Screenshot.

rebeccaxhawaii (rebeccaxhawaii):

\[(\sqrt{7})^{6x}=49x-6\]

OpenStudy (elonasushchik):

http://prntscr.com/atx9la

OpenStudy (elonasushchik):

yah hun

OpenStudy (elonasushchik):

I think its C

rebeccaxhawaii (rebeccaxhawaii):

no it would be \[(\sqrt{7})^{6x}=49^{x-6}\]

rebeccaxhawaii (rebeccaxhawaii):

also i also take that course and i can see that you are taking a quiz, test, or exam

rebeccaxhawaii (rebeccaxhawaii):

because http://prntscr.com/atxb2m if you moved more to the right it would show the amount of points you earn

OpenStudy (agent0smith):

Sqrt7 is 7^1/2 49 is 7^2 \[\Large (7^{1/2})^{6x}=(7^2)^{x-6}\]

OpenStudy (elonasushchik):

yeah im stuck on this one and done with the rest!

rebeccaxhawaii (rebeccaxhawaii):

we cant help on tests :/

OpenStudy (elonasushchik):

I got it thanx @agent0smith :*

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