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HEELPPPP 3(x-1)=2(x+8)
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Multiply each of the 2 terms of (x-1) by 3. Please show your work.
(3*x)-(3*-1)=(2*x)+(2*8)
\[3(x-1)=2(x+8) \] Distribute 3 to x and -1 then Distribute 2 to x and 8 When I say distribute, it means to multiply the terms in the parentheses by the number we are distributing(the number infront of the parentheses)
After we correctly distribute, we get this. \[3x - 3 = 2x + 16 \]
Now we isolate x
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Add 3 to both sides \[3x = 2x + 19\]
Subtract 2x from both sides \[x = 19\]
@ShadowLegendX shaddy let the user get the answer.
thank you so so so much
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