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Mathematics 6 Online
OpenStudy (logan13):

Help Please

OpenStudy (logan13):

http://prntscr.com/aubldo

OpenStudy (amilapsn):

factorize 108...

OpenStudy (logan13):

2^2 * 3^3

OpenStudy (amilapsn):

ok now you are closer to the answer...

OpenStudy (amilapsn):

now you just have to apply exponential rules...

OpenStudy (logan13):

108

OpenStudy (logan13):

@amilapsn

OpenStudy (amilapsn):

yep?

OpenStudy (logan13):

so A

OpenStudy (logan13):

@amilapsn

OpenStudy (amilapsn):

can you work out and show me how you got A?

OpenStudy (logan13):

im just giving a guess

OpenStudy (amilapsn):

you don't have to guess here... you know the exponential rule power of power right?

OpenStudy (logan13):

A is my guess i need this done

OpenStudy (logan13):

i guess its a because it has the same number you multiply by 2 @amilapsn

OpenStudy (amilapsn):

hay you can get it like this.... \(\sqrt[3]{108}\\ =108^{\frac{1}{3}}\\ =(2^2\times 3^3)^{\frac{1}{3}}\\ =(4\times3^3)^{\frac{1}{3}}\) off you go...

OpenStudy (logan13):

thanks for the help it means alot i got 2 more

OpenStudy (amilapsn):

Yw! But i've to go dr....

OpenStudy (logan13):

Okay

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