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Mathematics 10 Online
OpenStudy (quetzal):

Help ASAP

OpenStudy (quetzal):

http://prntscr.com/aud07u

OpenStudy (quetzal):

Some one please help me? @Qwertty123

OpenStudy (perl):

Can you show your work. We can't have radicals in the denominator.

OpenStudy (quetzal):

oh..Can you help me? I am not sure how to solve TBH.

OpenStudy (quetzal):

@Satellite73

OpenStudy (qwertty123):

I am not that good at these...

OpenStudy (quetzal):

@phi

OpenStudy (phi):

multiply top and bottom by sqrt(30) what do you get ?

OpenStudy (quetzal):

um..Like the whole thing by ^30 or each equation...

OpenStudy (phi):

I see one fraction. write sqr(30) next to the top and sqr(30) next to the bottom (i.e. next to the other sqr(30)) hopefully you know what sqr(30) * sqr(30) simplifies to ?

OpenStudy (quetzal):

yeah..But I am not getting anything..

OpenStudy (phi):

what is sqr(30) * sqr(30)?

OpenStudy (phi):

this is almost a definition. square root times itself "undoes" the square root.

OpenStudy (phi):

assuming you have the same thing inside each square root example sqr(7) * sqr(7) = 7 sqr(elephant) * sqr(elephant) = elephant etc.

OpenStudy (phi):

that is the bottom: sqr(30) * sqr(30) up top you have 4 * sqr(6) * sqr(30)

OpenStudy (phi):

if you multiply square roots, you can "merge them" like this 4 * sqr(6) * sqr(30) = 4 * sqr( 6 *30)

OpenStudy (phi):

so the top is \[ 4 \cdot \sqrt{6 \cdot 30}\] we should factor 30 into 6 * 5 \[ 4 \cdot \sqrt{6 \cdot 6 \cdot 5}\]

OpenStudy (phi):

if you have a pair of numbers inside a square root, you can "pull them out" and put one of them out front (multiplying)

OpenStudy (quetzal):

\[30^{30}\]

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