Question

Precalculus

http://prntscr.com/auedp7

Answer 1

I figured it out lol....

Answer 2

part b was 100*e^-0.153x and part c was 4.5 billion years or something like that (:

Answer 3

\[\int\limits \frac{ dA }{ A } = \int\limits k dt \]

\[Ln[\frac{ [A] }{ [A]_{0} }] = kt \]

\[e^{\ln(\frac{ A }{ A_{0} }} = e^{-kt}\]

\[\frac{ [A] }{ [A_{0}] } = e^{-kt}\]

\[[A_{0}]*e^{-kt} = [A]\]

Answer 4

LOL damn.. well here's some idea of how to get to that formula for half life @haleyelizabeth2017

Answer 5

Woah